Anons with <130 IQ need not read.
Lets say I have 40 hexagonal tiles stacked together in this way. I need to paint 21 of these with red paint, provided that all red tiles must be in contact with each other(all 21 red tiles should be touching each other, no red tile should be surrounded entirely by grey tiles)
How many ways of painting 21 tiles are there?
>If I pretend it's a special challenge exclusively for smart people, I can trick them into doing my homework for me.
The answer is 5. That's probably not the correct answer, I made a random guess, but even that's more than you deserve.
IMPOSSIBLE, only 1% can win this game! Try not to cum in 5 minutes!
I coomed
Allow me to ask. When you say 'ways' , do you mean distinct geometries or the number of all possible combinations such as for all sequence of R and G of length 40, and 21 R, there are s[i] = R and s[i-1] = s[i+1] = s[i-q] = s[i+q] = G for all values of q (assuming that when you stack your tiles you keep their number on each line constant and not a random function f(l) l being the line)
and we are supposed to give that number in terms of q?
Geometries = { block, block with n number of convex holes, with 0<=n<=19 }
Without information on how the tiles are set there can be a lot variations.
Do the tiles need to form a blob or can they also form a line? What about two lines, one red and one white, atop each other. What if I rotate a pattern by 60°? Do I get a new pattern?
Does it make a difference if I swap red tile 1 with red tile 2 or are they all interchangeable.
Dumb thread
This. The question is illposed unless you tell us the global geometry of the tiling and the symmetries you consider indistinguishable.
>provided that all red tiles must be in contact with each other(all 21 red tiles should be touching each other, no red tile should be surrounded entirely by grey tiles)
A hexagon can only touch up to 6 other hexagons. Therefore it cannot be in contact with all 20 other tiles. The problem has no solution. QED
Assuming you have a static arrangement of the tiles, find all permutations, then subtract all permutations that follow the rule. No idea what that is since we don't know the arrangement.
>Anons with <130 IQ need not read.
Shit, my IQ is exactly 129.99999999....
>all red tiles must be in contact with each other
what is this you moronic Black person? a red title sorrounded by 6 others cannot possible be in contact with a title touching any of the 6
go read a book and improve your "verbal IQ"
>pic
Finally, someone clearned the floor in E1M1.
bump
>i am too low iq to think up a legitimate reply
also too low iq to be in charge of thread order
After putting pen to paper I have concluded that it is an obscenely large number that you need not concern yourself with.
Considering however hexagonal rotational symmetry, the answer must have 6 as a factor.
Not necessarily. OP never specified the geometry of the array, so it can be 2 x 20 or 1 x 40, in which case it is too constrained for 6-fold symmetry.
Just paint a line down the middle, 21 tiles long. Total grey tiles touching for a perimeter will be 44+2=46. You only have 19 tiles left so you're a homosexual and your thread is gay.
What arrangement do you have when you want to make a "cell" or "blob" with 21 red tiles, and a closed perimeter of 19 grey tiles?
First question is, is 19 a possible perimeter?
out of 6^(40-1)/6^2 permutations (divided by 6^2 if you want unique ones that aren't just rotated/symmetrical versions of another one),
there is only
6^(21-1)/6^2 possible variations with 21 red tiles
to detect and remove cases where a tile is isolated, we just act as if non-red tiles never existed, can't have isolated ones if there's nothing to isolate them with.
now we have to add that there can be non-connected tiles, up to 5 sides unconnected, and that tiles can't overlap, meaning any other tiles must do a check
we simply remove cases where a tile has 0 connections, and sum multiply all cases where sides ARE connected
simple stuff:
6^(21-1)/6^2 -> ((6-1)!)^(21-1)/6^2
also you might wanna check wave function collapse delimited by member count
>Anons with <130 IQ need not read.
The only people who respond and waste brain power on this are all midwits.
You are treated like an idiot.