>Ohms law always appli-

>Ohms law always appli-

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  1. 2 years ago
    Anonymous

    I still remember blowing a lot of these before realizing I'm colourblind

    • 2 years ago
      Anonymous

      >Homosexual by disability

  2. 2 years ago
    Anonymous

    Why?

  3. 2 years ago
    Anonymous

    You're so moronic that you didn't even read the fricking law I mean: IT ONLY APPLIES TO OHMIC MATERIALS!!!!! You're so dumb.

    • 2 years ago
      Anonymous

      Definition of an Ohmic material: material that Ohm's law applies to
      Definition of Ohm's law: law that applies to Ohmic materials

  4. 2 years ago
    Anonymous

    It doesn't apply even to some average lamp, mate. I never saw anyone say Ohm's law always applies without also mention WHEN it "always" applies.

  5. 2 years ago
    Anonymous

    I've been trying to learn about voltage drops, and it didn't help that I tried to learn about LEDs at the same time.

    But I think I get it now? So it's not so much that they don't obey omhs law, it's like they turn into a different component when you change the voltage across them.

    • 2 years ago
      Anonymous

      Diodes have an exponential I-V relationship. Resistors have a linear I-V relationship.

      • 2 years ago
        Anonymous

        Not true.

        • 2 years ago
          Anonymous

          Exposing myself to morons that can't do science in IQfy, you are quite right.
          The relation is more like I=I0(exp(kV)-1). Pretty close tho

  6. 2 years ago
    Anonymous

    >>Ohms law always appli-
    i'm an electrical engineer. no one ever said "ohms law always applies. It was always presented in the context of purely resistive loads. frick, ohms law doesn't even apply to caps or coils.

    • 2 years ago
      Anonymous

      >ohms law doesn't even apply to caps or coils.
      Yes it does, moron, but with impedance instead of resistance.
      Never heard of [math]Z_L = jomega L[/math] and [math]Z_C = 1/j omega C[/math] ?

      • 2 years ago
        Anonymous

        >[math]j[/math]
        Sorry, I don't speak engineer

        • 2 years ago
          Anonymous

          >Sorry, I don't speak engineer
          Based i enjoyer

      • 2 years ago
        Anonymous

        Z=/=R idiot. at any given time V/I=/=Z either. what you are posting is a phasor which only applies in the monochromatic steady state. to say it's the same as ohms law is moronic. This is "electrons flowing in wires delivers energy" tier moronation.

        • 2 years ago
          Anonymous

          >monochromatic steady state. to say it's the same as ohms law is moronic
          What the frick are you even saying you fricking idiot? Im talking about caps and diodes, theyre are very fricking linear, even their transients are linear because theyre modeled by first order linear odes, the odes come from faradays law and from gauß' law when applied to lumped components. Want me to fricking derive them for you?
          >Monochromatic steady state
          Most jarring thing ive heard in a while, what the frick is up with this boars being filled with schizos and morons?
          By the way I am an actual electrical engineer, that has actually worked in power systems, specifically with modelling and simulation of large scale grids for very big fricking industrial plants.
          So shut the frick up, moron, for fricks sake

          • 2 years ago
            Anonymous

            >power systems
            No wonder you think that capacitors are Ohmic devices. Assuming you speak German because of the ß: Weißt du, was ein OHM'scher Widerstand ist? Warum heißt der wohl so?

          • 2 years ago
            Anonymous

            >OHM'scher Widerstand
            Kondensatoren haben Ohmnischer Widerstand
            Wenigstens, wenn die Frequenz festgesetzt ist

          • 2 years ago
            Anonymous

            I think, that's exactly what the other guy meant with "monochromatic steady state". Monochromatic = one colour = one frequency; steady = the frequency does not change

          • 2 years ago
            Anonymous

            Ohms law is a linear relationship between curremt and resistance, and its linear in a capacitor literally for any current.
            Who the frick says ohms law and thinks of a relationship w.r.t frequency? thats moronic

          • 2 years ago
            Anonymous

            By the way only highschool students call V = IR "ohms law" that's literally only valid for purely resistive circuits.
            Anyone else uses V = IZ or even J = sigma*D if you want to model an electric field

          • 2 years ago
            Anonymous

            Jesus, dude, stop making a fool of yourself

          • 2 years ago
            Anonymous

            >theyre are very fricking linear, even their transients are linear because theyre modeled by first order linear odes
            nobody tell this guy the solutions to first order ODEs are exponential functions.

          • 2 years ago
            Anonymous

            When people say linear they mean the system you absolute animal, not the fricking solutions.
            Moreover the solution is an exponential function with respect to time, its not an exponential relationship between voltage and current.

          • 2 years ago
            Anonymous

            charging capacitor transient
            V=(1-exp(-t))
            i=exp(-t)

            lets apply "ohms law"
            V/I=exp(t)-1=R

            cool, a capacitors resistance is an exponential function of time. so cool ohms law always applies, and these transients are linear.

        • 2 years ago
          Anonymous

          What delivers energy then?

          • 2 years ago
            Sam eggy

            He wants to say it's the fields but the movement of charges is necessary for it so it's mostly just a semantic squabble of no consequence.

          • 2 years ago
            Anonymous

            How do electrons carry energy

          • 2 years ago
            Sam eggy

            By their movement being necessary to create the magnetic field needed for there to be electromagnetic energy flux.
            You can say that they aren't literally the thing that carries the energy and the exact mechanism is something very interesting but categorically rejecting the idea is a little misleading.
            If you studied EM fields you already know this but if you are a layman this statement is just confusing.

          • 2 years ago
            Anonymous

            I am a freshman electricuck student so I don't know anything but it interests me

          • 2 years ago
            Sam eggy

            Ah, I see.
            I had EMF in my 3rd year of EE. Easily my favourite subject. Very math heavy though.

          • 2 years ago
            Anonymous

            What book did you use? I've tried to study Griffiths but I can't into 3d calculus yet so I figured I would come back to it after a year or two

          • 2 years ago
            Sam eggy

            I used books in my language written by my professors so I don't think I can give you any recommendations.

          • 2 years ago
            Anonymous

            I'll find a voltage meter to measure the difference between an LED and my Tazer and we can talk about V=I/R.

          • 2 years ago
            Sam eggy

            A diode doesn't have a constant R. A tazer doesn't either for that matter.

          • 2 years ago
            Anonymous

            >voltage meter
            >"difference between LED and tazer"
            >V=I/R
            so much about this post is hilarious, bravo

          • 2 years ago
            Anonymous

            Through kinetic energy

          • 2 years ago
            Anonymous

            *drifts at [math]10^{-5},mathrm{m/s}[/math]

          • 2 years ago
            Sam eggy

            Their kinetic energy cannot carry the energy. The electrons in a wire aren't slowing down when the energy is dissipated as heat. For a wire of uniform cross-sectional area and non-zero resistance, their average drift velocity will be constant while the energy is still delivered.

          • 2 years ago
            Anonymous

            electrons have a charge. charge creates a potential around is (this is called coulomb force and it was discovered hundreds of years ago). electrons can move freely in metal. chemical batteries and dynamos can be used to shunt these electrons. etc.
            I really hope you're under 18 for your own sake.

    • 2 years ago
      Sam eggy

      You can make it apply to capacitors. Capacitors still follow [math]V=IR[/math]. The capacitor acts as a voltage source so you have to include it.
      I guess an inductor would act as a current source analogous to the capacitor.

      >ohms law doesn't even apply to caps or coils.
      Yes it does, moron, but with impedance instead of resistance.
      Never heard of [math]Z_L = jomega L[/math] and [math]Z_C = 1/j omega C[/math] ?

      Not everything is purely a steady-state AC circuit. You can't solve transients like this.

      • 2 years ago
        Anonymous

        >Not everything is purely a steady-state AC circuit. You can't solve transients like this
        Yes you can, DEs for caps and inductors are first order and linear, take laplace transform, you then have
        [math](Y/X)(s) = 1/sC[/math] for caps and [math](Y/X)(s) = sC[/math] for inductors.

      • 2 years ago
        Anonymous

        >Not everything is purely a steady-state AC circuit. You can't solve transients like this.
        You do realize that the time dependent expressions for reactances are a thing?

  7. 2 years ago
    Anonymous

    What if I told you Resistance doesn't have to be a constant

  8. 2 years ago
    Anonymous

    >he thinks ohm's law is V=IR
    J=sigmaE where is sigma is the conductivity tensor blocks your path

    • 2 years ago
      Anonymous

      Reduces to [math]I = ZV[/math] for lumped components.
      Also, who the frick is actually solving maxwells equations in the real world using a fricking conductivity tensor ?

      • 2 years ago
        Anonymous

        Me every time I make a simple LED circuit.

  9. 2 years ago
    Anonymous

    >Ohms law always applies
    yes. name an example in which is doesn. reminder that ohm's is law states: "the current through a resistor is proportional to the voltage over it"

    • 2 years ago
      Anonymous

      That's not what ohm's law says at all. And even if that was it, that's wrong as well. Current is only proportional to the voltage drop over a component if it's a purely ohmic component. Diodes are not and the current through them does not follow a linear relationship with the voltage.

      • 2 years ago
        Anonymous

        >That's not what ohm's law says at all
        It is precisely what Ohm's law says. https://www.britannica.com/science/Ohms-law
        >The amount of steady current through a linear material is directly proportional to the potential difference, or voltage, across the material.
        What the FRICK do YOU think it says you coping, larping physicslet?

        • 2 years ago
          Anonymous

          I'd say saying it's just proportional is a little bit incomplete.
          Still, I don't know what you are smoking but diodes absolutely do not follow ohm's law.

          • 2 years ago
            Anonymous

            "The current through a linear material is proportional to the voltage over it."
            Diodes are not constructed from linear materials. So Ohm's Law still applies and there is no "violation". I smoke weed and swallow cum homosexual kys

  10. 2 years ago
    Anonymous

    OI! You aavin' a thread without me?

  11. 2 years ago
    Anonymous

    [math] V=IR [/math]

    [eqn] e^{ipi}+1=0 [/eqn]

  12. 2 years ago
    Anonymous

    Why does V = IR not apply to LEDs?

    • 2 years ago
      Anonymous

      I=exp(v)

      • 2 years ago
        Anonymous

        why tho

        • 2 years ago
          Anonymous

          >why tho
          read a book on solid state physics.

      • 2 years ago
        Anonymous

        Even if. Even if I=I0exp(V/V0)
        Just put
        V=RI
        V=RI0exp(v/v0)
        R=V/I0exp(V/V0)

  13. 2 years ago
    Anonymous

    -plies you engineer scum. Nobody said R needs to be a constant. R can vary by voltage, by current, by time.

    • 2 years ago
      Anonymous

      This.
      Classical Ohm's law is for idealized lumped elements where R is a constant proportionality factor between voltage and current.
      As soon as it changes with time/temperature/power/etc., R is no longer constant and just the derivative of the U-I-curve at any point in time. So Ohm's law still applies, just locally

      • 2 years ago
        Anonymous

        >So Ohm's law still applies, just locally
        what if my diode has a locally non-differentiable V-I curve

        • 2 years ago
          Anonymous

          don't worry about it, you will never encounter a diode with a non-differentiable V-I curve

  14. 2 years ago
    Anonymous

    You clearly havent mastered the art of pinning measurement errors to parasitic capacitance, go to reading experiment methodology please

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