This sequence of X and Y continues for an infinity. I don't know how to form an equation for X and Y. I need an equation/formula for this relation.
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This sequence of X and Y continues for an infinity. I don't know how to form an equation for X and Y.
[math]y=lfloor 0.25e^{0.28x}-0.1rfloor[/math]
This produces that sequence but I don't know if it's the expression the homosexual who came up with that wants.
Stfu you cum guzzling moronic homosexual. Every bad word youll try calling me APPLIES TO YOU Black person. YOUR moronic INBRED EQUATION IS THE STUPIDEST WAY THIS COULD BE DONE HOLY FRICK WHO THEY FRICK NEEDS DECIIMAL POINT FOR THIS YOU STUPID SHITSKINNED Black person DON'T FRICKING DARE REPLY TO THIS THREAD YOU ASS LICKING moronic INBRED CHILD OF Black folk
Give a better expression then you Black personhomosexual.
Before giving you something, I will give your mom my dick. My cum, my seed, shall develop in the very womb that once nourished you. Your brother, Anon 2.0, shall live up to your mom's expectations.
Your mom, my cum-taker, the bearer of children
I'm sorry that you're moronic enough to get filtered by this anon.
An actual solution written in TeX gets flamed for actually doing the work.
This place is overrun with children...
Good solution. Sorry op is moronic
Fails on the very next term moron
What do you mean fails?
For x=12 that function yields 7 instead of 6 and gets further divergent from there
>instead of 6
Where does it say 6??
It's ok, basic pattern recognition is not for everyone
why would 6 be the next number in the sequence?
OP doesn't specify what the 12th therm should be you homosexual.
18 y/o HS student here, please elaborate how you came up with this expression.
Anyways, if op is still conscious. Why not mult-part function?
[0,5]: f =0
(5,6] f = x-5
(6,7) f =1
[7,inf) f= x-6
Because that's lame. In that case, why not just define the function on an element-per-element basis?
>f(1)=0, f(2)=0, etc.
because his answer satisfies the request and it's conciser than what you propose
Continuous function is better probably. Depends on what question exactly was. I presume they’re always asking for continuity otherwise what’s the point
This is the better answer because of continuousness. Nice subtle effort anon
Also acceptable. Participation trophy
y=T(x-6)+T(x-7)*(x-7)
Where T is the heaviside theta function
[math] f(x)=-336 + 957.959524 x -1108.68464 x^2 + 698.971296 x^3 -269.302971 x^4 + 66.8979167 x^5 -10.9338310 x^6 + 1.16825397 x^7 -0.0785052910 x^8 + 0.00300925926 x^9 -0.0000501543210 x^{10} [/math]
Why.
https://oeis.org/search?q=0%2C0%2C0%2C0%2C0%2C1%2C1%2C2%2C3%2C4%2C5&language=english&go=Search
>continues for an infinity.
So what are the y values for 12, 13, 14, 20,and 100?
Not even worth writing in tex. Also, frick you because any finite sequence of numbers has infinite functions to describe it.
Y = FLOOR((X(X-1)(X-2)) / (37+13X))
[eqn]lim_{a rightarrow infty } e^{(b-7)^{a}} div (e^{(b-7)^{a}} + e^{(7-b)^{a}})[/eqn]
Sorry, you have to multiply by b in the beginning.
OP totally destroyed once again
There are infinite solutions.
test because op is a moron.
Huh. Sure, why not.
1/2*(-5 + x - abs(sgn(-6 + x*~~*(1 + sgn(-5 + x - abs(sgn(-6 + x*~~)
Probably the only valid answer ITT.
Dunno. But clearly from the picture, y converges to x from the right.
>continues for infinity? How exactly?
Y as
11 6
12 7
13 8
14 9
...
Or
12 5
13 5
14 5
15 5
16 6
17 6
18 7
19 8
20 9
...
Here you go:
[eqn]
y =
begin{cases}
0 &text{when }1leq xleq5\
1 &text{when }x = 6\
x-6 &text{when }x geq 7
end{cases}[/eqn]
[math]
f(n) = binom{n-1}{5} - 5 binom{n-1}{6} + 16 binom{n-1}{7} - 41 binom{n-1}{8} + 91 binom{n-1}{9} - 182 binom{n-1}{10}, quad n = 1,2, dots
[/math]